32x^2-60x=30x^2+40x

Solution for 32x^2-60x=30x^2+40x equation:

32x^2-60x=30x^2+40x

We move all terms to the left:

32x^2-60x-(30x^2+40x)=0

We get rid of parentheses

32x^2-30x^2-60x-40x=0

We add all the numbers together, and all the variables

2x^2-100x=0

a = 2; b = -100; c = 0;
Δ = b2-4ac
Δ = -1002-4·2·0
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-100}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+100}{2*2}=\frac{200}{4}
=50
$